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7p^2=-42-55p
We move all terms to the left:
7p^2-(-42-55p)=0
We add all the numbers together, and all the variables
7p^2-(-55p-42)=0
We get rid of parentheses
7p^2+55p+42=0
a = 7; b = 55; c = +42;
Δ = b2-4ac
Δ = 552-4·7·42
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-43}{2*7}=\frac{-98}{14} =-7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+43}{2*7}=\frac{-12}{14} =-6/7 $
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